(3d^2+3d)=(4d+2)

Solution for (3d^2+3d)=(4d+2) equation:

(3d^2+3d)=(4d+2)

We move all terms to the left:

(3d^2+3d)-((4d+2))=0

We get rid of parentheses

3d^2+3d-((4d+2))=0


We calculate terms in parentheses: -((4d+2)), so:

(4d+2)

We get rid of parentheses

4d+2

Back to the equation:

-(4d+2)


We get rid of parentheses

3d^2+3d-4d-2=0

We add all the numbers together, and all the variables

3d^2-1d-2=0

a = 3; b = -1; c = -2;
Δ = b2-4ac
Δ = -12-4·3·(-2)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-5}{2*3}=\frac{-4}{6}
=-2/3
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+5}{2*3}=\frac{6}{6}
=1
$